The price of the uniform is Rs. 250.
12 month=>900Rs+Uniform
1month:75 => 9month:675
675-650=25 =>price of Uniform
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12 month=>900Rs+Uniform
1month:75 => 9month:675
675-650=25 =>price of Uniform
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Question does not clarify if its simple interest or compound interest
Sum of all numbers in series= 870 (I.e 312+162+132+142+122)
Average=sum of numbers/count of numbers
Average= 870/5
= 174
Answer: 40
Explanation:
800*(25/100) = 200 —- 5
? —- 1 => Rs.40
The Price per KG is Rs.40(After Reduction)
Let X is price of the product and Y is KGs he can get for Rs.800
so XY = 800
By the reduction of 25% in the price he can get Y+5 KGs for 800
so (X - 25X/100)(Y+5) = 800
(X - X/4)(Y+5) = 800
(3X/4)(Y+5) = 800
3XY + 15X = 800 * 4 = 3200
3*800 + 15X = 3200
15X = 800
X = 53.333(Original Price)
Reduced Price(25%) = 13.333
Price After Reduction is Rs.40
900
my guess is 900.
225/400 = 9*25/16*25 which 9 and 16 is the squared of 3 and 4 so:
25*25/36*25
800?
2->4->6->8
25->00->25->00
But there is that weird "::".
Out of 10 persons, 4 are graduates; so, (10 - 4) = 6 are under-graduates.
If there is no restriction, any three can be chosen from the ten in (10C3) = 120 ways.
Now, if all three chosen are under-graduates; it can take place in (6C3) = 20 ways.
Therefore, the probability that there will be no graduate among the three chosen = (20 / 120) = (1 / 6).
Therefore, the probability that there will be at least one graduate among the three chosen = {1 - (1 / 6)} = (5 / 6) = 0.8333.
30mins
Let the total time taken to fill the tank be x minutes.
Then, work done by B in half hour + work done by (A+B) in half hour =1.
(
40
1
×
2
x
)+(
60
1
+
40
1
)×
2
x
=1
⇒
80
x
+
48
x
=1
⇒
240
3x+5x
=1
⇒8x=240
⇒x=30 min
68 is the least number when divided by 8, 12, 18 and 24 leaves the remainders 4, 8, 14 and 20
FYI
125 : 343 :: 343 : __
(5,7,11,........)
125=5*5*5 (prime no.)
345=7*7*7 (prime no.)
1331=11*11*11 (prime no.)
Ans- 1331
729
Here 125
1+2=3, 2+2=4, 5-2=3
So similarly
3+2=5, 4+2=6, 3-2=1
Answer: 561