Questions in: Aptitude

Answer: 66.67 km approx.

Solution:

Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,

u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr

Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)

0. The bee can never fly away from the first train that it's located on simply because the speed of the bee is less than the train

Beespeed*(distance/speedA+speedB)
100/3 km

134

6*6=36 medals
6 days

1st day=1+35/7=6 remaining 30 medals
2nd day=2+28/7=6 remaining 24 medals
3rd day=3+21/7=6 remaining 18 medals
...
6th day 6 medals

take goat from one side and leave it another side and then come back another side and carry cabbage from one side leave it near goat and carry goat back to other side and then carry wolf leave it another side with cabbage come back to
goat side and carray goat to other side not all three are there on another side

He will take the goat first to the other side leaving the wolf with the cabbage, when he returns, he will take the wolf next and bring back the goat with him, he will then take the cabbage to the other side and come back for the goat.

1/4, 1/8
4*8=32
32-4=28
28-8=20
28*20/(4^2)=35.00

I think it's 32 not 37

If x is no. of coins, he divide into unequal number,
let x=x1+x2
given condition,
37(x1-x2)=(x1^2-x2^2)
37(x1-x2)=(x1+x2)(x1-x2) b'c0z (a^2-b^2)=(a+b)(a-b)
x1-x2 cancel on both side we remain with
37=(x1+x2)=x
so no. of coins=37

Y R G
B B G
Y G Y

The definition of left and right depends on the observer and
is reversed when facing the opposite direction. The
definition of up and down does not depend on the orientation
of the observer.

Answer: 3121 gold coins
Let total no of coins be M
Let the disbursement D to each son:

D1 = 1 + (M – 1)/5 = (M + 4)/5
D2 = 1 + ( M – D1 -1)/5 = (D1) * 4/5
D3= (D2) * 4/5
D4= (D3) * 4/5
D5= (D4) * 4/5
Total disbursements to sons=
= ∑D= (M+4)*1/5[ 1+4/5+(4/5)(4/5)+ (4/5)(4/5)(4/5)+(4/5)(4/5)(4/5)(4/5) ]
= (2101/3125)*(M+4)
Thus balance left for daughters =M-{(2101/3125)*(M+4)}
=(1024M-8404)/3125
This balance should be a positive integer ( assuming M and all disbursements are full coins )
Thus 1024M-8404 should be a multiple of 3125….so….
1024M - 8404 = N*3125 where N is an integer
Using Python code:
n=int(input("Enter num n: "))
X=int()
a=int()
a=0
X=' '
for a in range(0,n+1):
a=a+1
X= (3125*a + 8404)/1024
if (3125*a + 8404)% 1024== 0:
print(X,a)
Enter num n: 10000
3121.0 1020
6246.0 2044
9371.0 3068
12496.0 4092
15621.0 5116
18746.0 6140
21871.0 7164
24996.0 8188
28121.0 9212
We get minimum value of N = 1021 and M = 3121 gold coins

Correct last line in previous post. Minimum value of N = 1020

76

Answer= 76 diamonds

Let total diamonds = M

Thief 1 ( T1 ) took = M/2 +2

T2 = M/4 + 1

T3 = M/8 + 1/2

T4= M/16 + 1/4

T5= 1
Adding them should sum up to M
Thus the equation: M = M*(15/16) + 19/4 ......thus M = 76

T1, T2 , T3, T4, T5 are 40, 20, 10, 5 , 1 respectively

64

answer is 12
bcoz
there are 36 people and atmost he can shake for 3 people so
36/3=
12

answer is one

Correct answer- 192

Number 3 in 1-100 comes 20 times.
101-200-> 20 times
201-300-> 20 times
301-400->120 times
401-500-> 20 times
501-600-> 20 times
601-700-> 20 times
701-800-> 20 times
801-900-> 20 times
901-1000-> 20 times
Total times: 300 times (any no. from 1 to 9 except 0 will occur 300 times)
8 based planet.. then
3*8^2 + 0*8^1 + 0*8^0 = 192

Put switch 1 on and leave it on for 2 minutes, then switch it off.
Put switch 2 on and leave it on, then walk into the room.
If the light is on, the answer is switch 2.
If the light is off but the bulb is warm when you feel it, the answer is switch 1.
If the light is off and the bulb is cold when you feel it, the answer is switch 3.

First of all we have to switch on the first switch and have to leave it for 6 or more minutes. After that, we have switch off it and second switch have to be turn on. Now immediately go to the room and touch the bulb. If the bulb is hot, first switch is the answer. If the bulb is already glowing, second one is the answer. if bulb is neither glowing nor hot, third one is the answer.