Questions in: Gate

manish soni tagore collage jaipur
ph:9785261817
e_mail:monupanhar@yahoo.comf;
hapy to help;
#include<iostream>
#include<stdio.h>
#include<conio.h>
using namespace std;
struct complex
{
int real;
int img;
};
void getdata(complex &);
complex sum(complex,complex);
complex mult(complex,complex);
void display(complex);
int main()
{
complex c1,c2,c3,c4;
getdata(c1);
getdata(c2);
c3=sum(c1,c2);
cout<<"Sum= ";
display(c3);
c4=mult(c1,c2);
cout<<"MULT= ";
display(c4);
getch();
return 0;
}
complex sum(complex c1,complex c2)
{
complex c;
c.real=c1.real+c2.real;
c.img=c1.img+c2.img;
return c;
}
void display(complex c)
{
cout<<c.real<<"+"<<c.img<<"i"<<endl;
}
complex mult(complex c1,complex c2)
{
complex c;
c.real=c1.real*c2.real-c1.img*c2.img;
c.img=c1.img*c2.real+c1.real*c2.img;
return c;
}
void getdata(complex &c)
{
cout<<"Enter first complex number:"<<endl;
cout<<"Enter real ";
cin>>c.real;
cout<<"Enter img ";
cin>>c.img;
}

A.BHA RAJA
THENNAGALAPURI
#include<iostream.h>
#include<conio.h>
class complex
{
int r,i;
public:
{
void getdata(int a,int b)
{
r=a; i=b;
}
complex operator+(complex,complex);
void display(void);
};
complex complex :: operator+(complex a,complex b)
{
complex c;
c.r=a.r+b.r;
c.i=a.i+b.i;
return c;
}
void complex :: display(void)
{
cout<<r<<"+i"<<i<<"n";
}
void main()
{
complex p,q,r;
int n,m;
clrscr();
cout<<"Enter the real number:";
cin>>n;
cout<<"Enter the imag number:";
cin>>m;
p.getdata(n,m);
cout<<"Enter the real number:";
cin>>n;
cout<<"Enter the imag number:";
cin>>m;
q.getdata(n,m);
r=p+q;
p.display(p);
q.display(q);
r.display(r);
getch();
}

The interview for oces/dgfs is to test how much a candidate
knows about a particular subject. The will ask almost about
all the subjects u have in ur stream(computer/electronics).
They start with ur subjects in 2nd and 3rd year and if u
answer all questions then only they will go to other subjects.
One thing for sure they will start with ur BE project. They
will ask u question on a particular topic unless and untill
u dont give up answering on that topic.
For computer subjects like OOPS,COA,OS,Automata,System
Programming,Database,ComputerGraphics,ComputerNetworks are a
must study.

19 th of may about 9 am

M F= CT Ratio * PT Ratio {of ct & pt}
----------------------------------------X Dial mf of meter
CT Ratio * PT Ratio { of trivector meter}

It will contains some questions from
Linux/Unix,Databases,C,C++ and Java.All are the objective
model questions.

hi all
here are some of the memory based questions which were asked
in NIC Test on 22nd Feb 2009
testing defn (very puzling)
integration testing ->1)botto up 2)top down 3)embedded 4)none
boot sector virus is?
OFDM stands for?
ieee 802.11 uses 1)csma 2)csma/cd 3)csma/ca 4)token ring
smallest microprocessor form intel-> atom
alu uses memory as 1)control memory 2)i/o device 3) ram 4)
register
ACID stands for?
command to contert FAT into NTFS?
given was: access without cache=20ns; with cache=10ns; cache
access time=5ns; find hit?
normalization; which form is based upon .....?
which of the following is dba responsibilty? 1)schema design
2)security access....
spiral model gurantees 1)quality 2)..
usb 2.0 speed ? 1)480Mbps...
loop back address is ...?
RAID is concerned with 1)hard disk 20...
which one sure constant bandwidth? 1)ckt switching 2)cell
switching 3)...
class c defalt subnet mask was given and we were asked to
tell how many usable hosts can be connected there? 1)254
2)255...
which one of the following is a spooled device? 1)printer
2)monitor....
FDDI uses 1)token ring 2)bus topology 3)star topolgy..
if a file is downloded in 2 minutes using a 56kbps modem,
what is the size of max download?
add lin = 32; data line = 16 ; max memory it will support
will be? 1)4GB 2)32GB 3....
all the best !!
regards
pankaj

networking is necessary for the sharing of data and passage
of data from different location in a secure way.

the shhared global computing network

The shared global computing network. A network based on
standards including Internet Protocol (IP), Simple Mail
Transfer Protocol (SMTP) and the Domain Name System (DNS),
which enables global communications between all connected
computing devices. It provides the platform for web
services and the WorldWide Web.

indian agriculture research institute -- new delhi
ccs national institute of agricultural marketing -- jaipur

new delhi

0,4,18,48,200

0, 4, 18, 48, 100 (n * n * (n -1)) and value of n should
starts from 1

k = 5
and
a = -5
because
-9+2k = 1 => k = 5
and
a=10-8k+k^2 => a = -5

consider this form:
(divisor)x(quotient)+remainder=dividend
(x^2-2x+k)*(a0x^2+a1x+a2)+x+a=x^4-6x^3+16x^2-25x+10
compare the co-efficients to get a and k.
expect ans to be a=-10, k=4.

1
2=(1+1)1
6=(2+1)2
21=(6+1)3
88=(21+1)4
So 445=(88+1)5
& 2676=(445+1)6
Simple logic :-)

(x*i+i)
1*1+1=2,
2*2+2=6,
6*3+3=21,
21*4+4=88,
88*5+5=445,
445*6+6=2676.
1,2,6,21,88,445,2676.