The total distance traveled by the bee is 80 kilometers.
Answer: 66.67 km approx.
Solution:
Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,
u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr
Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)
0. The bee can never fly away from the first train that it's located on simply because the speed of the bee is less than the train
Beespeed*(distance/speedA+speedB)
100/3 km
Unicast IP addresses are unique identifiers assigned to a single network interface on a device. They enable one-to-one communication, allowing data packets to be sent from one specific source to one specific destination. This ensures that the data reaches only the intended recipient, making it suitable for applications like web browsing and email.
1. Take the goat across the river first and leave it on the other side.
2. Go back alone and take the wolf across the river.
3. Leave the wolf on the other side but take the goat back with him to the original side.
4. Leave the goat on the original side and take the cabbage across the river.
5. Leave the cabbage with the wolf on the other side and go back alone to get the goat.
6. Finally, take the goat across the river.
Now all three (wolf, goat, and cabbage) are safely on the other side.
take goat from one side and leave it another side and then come back another side and carry cabbage from one side leave it near goat and carry goat back to other side and then carry wolf leave it another side with cabbage come back to
goat side and carray goat to other side not all three are there on another side
He will take the goat first to the other side leaving the wolf with the cabbage, when he returns, he will take the wolf next and bring back the goat with him, he will then take the cabbage to the other side and come back for the goat.
The hare should increase its speed by a factor of 5.
1/4, 1/8
4*8=32
32-4=28
28-8=20
28*20/(4^2)=35.00
The number of rabbit pairs after n months follows the Fibonacci sequence. The number of pairs after n months is F(n+1), where F is the Fibonacci number. For example, after 1 month: 1 pair, after 2 months: 1 pair, after 3 months: 2 pairs, after 4 months: 3 pairs, after 5 months: 5 pairs, and so on.
The EIB parameter used for implementing the Pseudo-Conversational technique in CICS is `EIBCALEN`, which indicates the length of the data being passed. The CICS command used is `EXEC CICS RETURN`. This allows the program to return control to CICS while retaining the context for the next interaction. For a single Program Control Table (PCT) and Program Processing Table (PPT) entry, you can define the program in the PCT and ensure it is set to use the same PPT entry for subsequent calls.
A mirror reverses left and right because it reflects the image directly back to you, creating a lateral inversion. However, it does not reverse up and down because the orientation of those axes remains the same.
The definition of left and right depends on the observer and
is reversed when facing the opposite direction. The
definition of up and down does not depend on the orientation
of the observer.
DTB stands for Data Table Block, which is a structure used in CICS to manage and store data in a tabular format for efficient access and processing.
One way to get an estimate of an object's size in Java is to use getObjectSize(Object) method of the Instrumentation interface introduced in Java 5. As we could see in Javadoc documentation, the method provides “implementation-specific approximation” of the specified object's size.
Yes, a table entry is required for a Temporary Storage (TS) queue in CICS.
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